Optimal. Leaf size=76 \[ -\frac{(1-2 x)^{5/2}}{55 (5 x+3)}+\frac{4}{55} (1-2 x)^{3/2}+\frac{12}{25} \sqrt{1-2 x}-\frac{12}{25} \sqrt{\frac{11}{5}} \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right ) \]
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Rubi [A] time = 0.0182215, antiderivative size = 76, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {78, 50, 63, 206} \[ -\frac{(1-2 x)^{5/2}}{55 (5 x+3)}+\frac{4}{55} (1-2 x)^{3/2}+\frac{12}{25} \sqrt{1-2 x}-\frac{12}{25} \sqrt{\frac{11}{5}} \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right ) \]
Antiderivative was successfully verified.
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Rule 78
Rule 50
Rule 63
Rule 206
Rubi steps
\begin{align*} \int \frac{(1-2 x)^{3/2} (2+3 x)}{(3+5 x)^2} \, dx &=-\frac{(1-2 x)^{5/2}}{55 (3+5 x)}+\frac{6}{11} \int \frac{(1-2 x)^{3/2}}{3+5 x} \, dx\\ &=\frac{4}{55} (1-2 x)^{3/2}-\frac{(1-2 x)^{5/2}}{55 (3+5 x)}+\frac{6}{5} \int \frac{\sqrt{1-2 x}}{3+5 x} \, dx\\ &=\frac{12}{25} \sqrt{1-2 x}+\frac{4}{55} (1-2 x)^{3/2}-\frac{(1-2 x)^{5/2}}{55 (3+5 x)}+\frac{66}{25} \int \frac{1}{\sqrt{1-2 x} (3+5 x)} \, dx\\ &=\frac{12}{25} \sqrt{1-2 x}+\frac{4}{55} (1-2 x)^{3/2}-\frac{(1-2 x)^{5/2}}{55 (3+5 x)}-\frac{66}{25} \operatorname{Subst}\left (\int \frac{1}{\frac{11}{2}-\frac{5 x^2}{2}} \, dx,x,\sqrt{1-2 x}\right )\\ &=\frac{12}{25} \sqrt{1-2 x}+\frac{4}{55} (1-2 x)^{3/2}-\frac{(1-2 x)^{5/2}}{55 (3+5 x)}-\frac{12}{25} \sqrt{\frac{11}{5}} \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )\\ \end{align*}
Mathematica [A] time = 0.0299601, size = 58, normalized size = 0.76 \[ \frac{1}{125} \left (\frac{5 \sqrt{1-2 x} \left (-20 x^2+60 x+41\right )}{5 x+3}-12 \sqrt{55} \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )\right ) \]
Antiderivative was successfully verified.
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Maple [A] time = 0.009, size = 54, normalized size = 0.7 \begin{align*}{\frac{2}{25} \left ( 1-2\,x \right ) ^{{\frac{3}{2}}}}+{\frac{62}{125}\sqrt{1-2\,x}}+{\frac{22}{625}\sqrt{1-2\,x} \left ( -2\,x-{\frac{6}{5}} \right ) ^{-1}}-{\frac{12\,\sqrt{55}}{125}{\it Artanh} \left ({\frac{\sqrt{55}}{11}\sqrt{1-2\,x}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.54854, size = 96, normalized size = 1.26 \begin{align*} \frac{2}{25} \,{\left (-2 \, x + 1\right )}^{\frac{3}{2}} + \frac{6}{125} \, \sqrt{55} \log \left (-\frac{\sqrt{55} - 5 \, \sqrt{-2 \, x + 1}}{\sqrt{55} + 5 \, \sqrt{-2 \, x + 1}}\right ) + \frac{62}{125} \, \sqrt{-2 \, x + 1} - \frac{11 \, \sqrt{-2 \, x + 1}}{125 \,{\left (5 \, x + 3\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.60004, size = 198, normalized size = 2.61 \begin{align*} \frac{6 \, \sqrt{11} \sqrt{5}{\left (5 \, x + 3\right )} \log \left (\frac{\sqrt{11} \sqrt{5} \sqrt{-2 \, x + 1} + 5 \, x - 8}{5 \, x + 3}\right ) - 5 \,{\left (20 \, x^{2} - 60 \, x - 41\right )} \sqrt{-2 \, x + 1}}{125 \,{\left (5 \, x + 3\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 2.1076, size = 100, normalized size = 1.32 \begin{align*} \frac{2}{25} \,{\left (-2 \, x + 1\right )}^{\frac{3}{2}} + \frac{6}{125} \, \sqrt{55} \log \left (\frac{{\left | -2 \, \sqrt{55} + 10 \, \sqrt{-2 \, x + 1} \right |}}{2 \,{\left (\sqrt{55} + 5 \, \sqrt{-2 \, x + 1}\right )}}\right ) + \frac{62}{125} \, \sqrt{-2 \, x + 1} - \frac{11 \, \sqrt{-2 \, x + 1}}{125 \,{\left (5 \, x + 3\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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